Coding - Algo/python
[백준] 2468번:안전 영역 (python 파이썬)
jainn
2021. 2. 19. 17:37
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문제
풀이
물에 잠기지 않는 부분들만 visited로 방문표시를 하면서 dfs를 돌려줬다.
소스코드
import sys
input = sys.stdin.readline
sys.setrecursionlimit(100000)
def dfs(y, x, a):
dx = [-1, 1, 0, 0]
dy = [0, 0, -1, 1]
visited[y][x] = 1
for i in range(4):
nowx, nowy = dx[i]+x, dy[i]+y
if 0<=nowx<n and 0<=nowy<n and visited[nowy][nowx]==0 and arr[nowy][nowx]>a:
dfs(nowy, nowx, a)
n = int(input())
arr = [list(map(int, input().split())) for _ in range(n)]
List = []
minn = 0
maxn = 0
for i in range(len(arr)):
List.append(max(arr[i]))
List.append(min(arr[i]))
minn = min(List)
maxn = max(List)
ans = 1
for a in range(minn, maxn+1):
cnt = 0
visited = [[0]*n for _ in range(n)]
for i in range(n):
for j in range(n):
if arr[i][j]>a and visited[i][j] == 0:
dfs(i, j, a)
cnt += 1
if cnt>ans:
ans = cnt
print(ans)
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